Given set :
154,109,137,115,152,140,154,178,80,103,126,126,137,165,165,129,200,148.
Rewrite the given data set from least to highest values.
80, 103, 109, 115, 126, 126, 129, 137, 137, 140, 148, 152, 154, 154, 165, 165, 178, 200.
Recall that a data point is an outlier if it is over 1.5 times the IQR below the first quartile or 1.5 times the IQR above the third quartile.
We know that
![\text{IQR}=Q_3-Q_1](https://img.qammunity.org/2023/formulas/mathematics/college/z5fcagr9r4h439y7ygryws4sv9700x50qy.png)
![Q_3=The\text{ third quartile = The median of the upper half of the data set.}](https://img.qammunity.org/2023/formulas/mathematics/college/tmeioa2ui9wg8858eslcduvr0zwrzixdsm.png)
![Q_1=The\text{ first quartile = The median of the lower half of the data set.}](https://img.qammunity.org/2023/formulas/mathematics/college/9xs870d8337piw45vagsug4cr3eglrbv00.png)
The upper half of the data set is
{137, 140, 148, 152, 154, 154, 165, 165, 178, 200}
The number of data in the set is even.
There are two middle terms in this upper half of the given set. That are 154 and 154.
![Q_3=(154+154)/(2)=154](https://img.qammunity.org/2023/formulas/mathematics/college/zgdtafgmjfxyl4czamlhe4mzv8vxelq0r1.png)
The lower half of the data set is
{80, 103, 109, 115, 126, 126, 129, 137, 137, 140}
The number of data in the set is even.
There are two middle terms in this lower half of the given set. Which are 126 and 126.
![Q_1=(126+126)/(2)=126](https://img.qammunity.org/2023/formulas/mathematics/college/euwj9c9894mng1gtevack07qv5xwqrbenl.png)
Substitute known values in the IQR formula.
![\text{IQR}=154-126=28](https://img.qammunity.org/2023/formulas/mathematics/college/bhv3ateitfh2af9kbbzb97uxuj8tlm396g.png)
We get IQR=28.
![\text{HIgher outlier }\ge Q_3+(1.5* IQR)](https://img.qammunity.org/2023/formulas/mathematics/college/6025gqtvhxuxjfknn88l6cz6vk097scvb3.png)
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