Question

How many moles of HCL are required to prepare 0.80L of a 0.5M HCL solution

Answer 1

`0.4\text{ mol}`

Step-by-step explanation:

Here, we want to get the number of moles

Mathematically:

`Number\text{ of moles = molarity }*\text{ volume}`

We have that as:

`Number\text{ of moles = 0.5 }*\text{ 0.8 = 0.4 mol}`