Question

This is the exercise I have to do to practice for my GED I’m a six year old woman I’m trying to figure this out I know I have inserted in the formula and it says just like example 3 I will insert example 3 in the text hereA survey indicates that for each trip to a supermarket, a shopper spends an average of 43 minutes with a standard deviation of 12 minutes in the store. The lengths of time spent in the store are normally distributed and are represented by the variable X. A shopper enters the store. Find the probability that the shopper will be in the store for each interval of time listed below. a) Find the probability that the shopper will be in the store between 33 and 66 minutes.b)) Find the probability that the shopper will be in the store for more than 39 minutes. Hint: Convert the normal distribution X to Standard normal using Z formula Z=(X-μ)/σ and then look the Z-values from the table and then find the probability.Hint: Convert the normal distribution X to Standard normal using Z formula Z=(X-μ)/σ and then look the Z-values from the table and then find the probability.Please help me answer properly so I can start the exercise so I can be fish prayers for the GED practice course

Answer 1

Given:

The lengths of time spent in the store are normally distributed and are represented by the variable X

The survey indicates that for each trip to a supermarket, a shopper spends an average of 43 minutes with a standard deviation of 12 minutes in the store.

so, the mean = μ = 43

And the standard deviation = σ = 12 minutes

We will find the probability that supermarkets between 31 and 58 minutes

We will use the following formula to convert to the z-scores

`Z=((X-μ))/(σ)`

So, we will find Z when x = 31 and When x = 58

`\begin{gathered} x=31\rightarrow z=(31-43)/(12)=(-12)/(12)=-1 \\ \\ x=58\rightarrow z=(58-43)/(12)=(15)/(12)=1.25 \end{gathered}`

So, we will find the probability of P (-1 < z < 1.25)

From the tables of the z-score:

[tex]P(-1So, the answer will be 0.7357