Question

A metal rod 800mm long is heated from 10°C to 95°C.If it expands by 1.36mm,the linear expansivity of the metal is?

Answer 1

2 x 10^(-5)

Step-by-step explanation:

The linear expansivity α can be calculated using the following equation:

`\Delta L=\alpha\cdot\Delta T\cdot L`

Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:

`\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}`

Then, solving for α, we get:

`\begin{gathered} 1.36=\alpha(68000) \\ (1.36)/(68000)=(\alpha(68000))/(68000) \\ 2*10^(-5)=\alpha \end{gathered}`

Therefore, the linear expansivity of the metal is 2 x 10^(-5)