The Point-Slope form of the equation of a line is:
![y_{}-y_1=m(x-x_1)_{}](https://img.qammunity.org/2023/formulas/mathematics/college/8tywdgemstmml0t1apmjwypm64ynftpaxv.png)
Where "m" is the slope of the line and this is a point on the line:
![(x_1,y_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/x550ag71r3nlvmk4as4e3r7sboim1mls0a.png)
You can find the slope of a line using this formula:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
In this case, knowing that this line passes through these points:
![(-2,-2);\mleft(2,1\mright)](https://img.qammunity.org/2023/formulas/mathematics/college/9z8iti1owiaczkzddm66ddhnmdbk8tqukw.png)
You can set up that:
![\begin{gathered} y_2=-2 \\ y_1=1 \\ x_2=-2 \\ x_1=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/baeresdoxgjwarngmfditlwaspzyu1q7ff.png)
Substituting values into the formula and evaluating, you get:
![m=(-2-1)/(-2-2)=(-3)/(-4)=(3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/f4cijihr1f99ohj6yz7ig6fez9ngef20yn.png)
Knowing the slope and coordinates of two points on the line, you can set up these two equations for this line:
1. First equation:
![\begin{gathered} y-(-2)=(3)/(4)(x-(-2)) \\ \\ y+2=(3)/(4)(x+2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vx8tygl2uvdxdrfvhy513kdbtf7z7qxyag.png)
2. Second equation:
![y-1=(3)/(4)(x-2)](https://img.qammunity.org/2023/formulas/mathematics/college/shgrynylqq85wsxof7h9ott1xucb657uco.png)
The answers are: Option A and Option B.