Question

What is the electric field strength at a distance of 0.9 m from a charge of 5.71 x 10^-6 C?

Answer 1

Given:

`\begin{gathered} Q=5.71*10^(-6)\text{ C} \\ r=0.9\text{ m} \end{gathered}`

The electric field strength is given as,

`E=(KQ)/(r)`

Here, K is the electrostatic constant.

Putting the values,

`\begin{gathered} E=(9*10^9*5.71*10^(-6))/((0.9)^2) \\ =63444.44\text{ N/C} \end{gathered}`

Therefore, the electric field strength is 63444.44 N/C.