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Factoring binomials math

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1 vote

we have the expression


x^3-125

we have that

x=5 is a zero of the given equation

so

Divide x^3-125 by (x-5)

x^3-125 : (x-5)

x^2+5x+25

-x^3+5x^2

---------------

5x^2-125

-5x^2+25x

------------------

25x-125

-25x+125

----------------

0

therefore

x^3-125=(x-5)(x^2+5x+25)

the answer is the fourth option

User Kshen
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