Given:
4 5 6 7
Given that you picked a card at random, without replacement, you then pick a second card at random.
Let's find the probability of picking an even number and then picking an even number.
Number of possible events = 4
Number of even numbers = 4, 6, ==> 2 even numbers.
Hence, to find the probability, we have:
![\begin{gathered} P=(2)/(4)*(1)/(3) \\ \\ P=(2*1)/(4*3) \\ \\ P=(2)/(12)=(1)/(6) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9qq5jz2ko95dooayg8pp4srpxk24btplmq.png)
Therefore, the probability of picking an even number and then picking an even number is 1/6.
ANSWER:
![(1)/(6)](https://img.qammunity.org/2023/formulas/mathematics/high-school/s2sdjtchslkb90he84q1tkyhaenfcyiyvp.png)