Question

7. A plumber notices a faucet leaking at a rate of 0.5 milliliters per second. What is the rate of the leak in liters per hour?

Answer 1

We need to convert the units:

• milliliter to liter;

,

• second to hour.

Since each milliliter (mL) is the thousandth part of one liter (L), we have:

mL = 0.001 L

Also, since each hour (h) has 60 minutes (min), and each minute has 60 seconds (s), we have:

1 h = 60 min = 60 * 60 s = 3600 s

s = (h/3600)

Now, we can rewrite the rate of the leak as follows:

`(0.5mL)/(s)=(0.5\cdot0.001L)/((1)/(3600)h)=(0.0005L)/(h)\cdot3600=(1.8L)/(h)`