Question

Find the length of the hypotenuse in a 45-45-90 triangle with legs 8 cm (draw a picture):O 11.31 cmO 5.66 cm08.66 cmO 10 cm

Answer 1

Our triangle would be:

Using the pythagorean theorem, we get that:

`h^2=8^2+8^2`

Solving for h :

`\begin{gathered} h^2=8^2+8^2\rightarrow h=\sqrt[]{8^2+8^2} \\ \Rightarrow h=11.31 \end{gathered}`

Thereby, the hypotenuse measures 11.31 cm