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Solve sin(x)= -.036 on the interval 0 is less than or equal to x which is less than 2pi

User Gary Coady
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In the interval


0\leq x<2\pi

We have two values that sin is negative. I will draw a trigonometric circle:

We can find these values using a calculator.


x\text{ = }\sin ^(-1)(-0.36)

This will give -21.1 degrees. If we start counting from zero, one complete circle is 360 degrees. So to find x2 we have to do:


x2\text{ = 360 - 21.1 = 339 degr}ees

And to find x1 we have to add 21.1 degrees counting from the start that is now 180:


x1=180+21.1\text{ = 201.1 degre}es

We do this process because we have two angles that give the same sin value, and they are symmetric compared to the sin axis!

Solve sin(x)= -.036 on the interval 0 is less than or equal to x which is less than-example-1
User Roman Timushev
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