In the interval
![0\leq x<2\pi](https://img.qammunity.org/2023/formulas/mathematics/high-school/ppt4jcuuhs8svs4g5fq3d4kd03nqgq01i2.png)
We have two values that sin is negative. I will draw a trigonometric circle:
We can find these values using a calculator.
![x\text{ = }\sin ^(-1)(-0.36)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zyuvp1xv9la3nkizh8g8ausn09r445j7yo.png)
This will give -21.1 degrees. If we start counting from zero, one complete circle is 360 degrees. So to find x2 we have to do:
![x2\text{ = 360 - 21.1 = 339 degr}ees](https://img.qammunity.org/2023/formulas/mathematics/high-school/axbohmlosfsjyjhyr3i4xd54lnpirryioe.png)
And to find x1 we have to add 21.1 degrees counting from the start that is now 180:
![x1=180+21.1\text{ = 201.1 degre}es](https://img.qammunity.org/2023/formulas/mathematics/high-school/is0lb0rz3xoyft78enssii8wp23fnplz8z.png)
We do this process because we have two angles that give the same sin value, and they are symmetric compared to the sin axis!