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Write the equation of the circle with the given center and radius center (0,0) r=12

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The equation of the circle can be determined as follow:

If you have the center in the point (0,0)

and r = 12

You use the next formula:


d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

Where

the d is equal to the r

x1 and y1= (0,0) (the center point)

x2 and y2 = (x,y)

Then we have:


r=\sqrt[]{(x_{}-0)^2+(y_{}-0)^2}
r^2=(\sqrt[]{(x_{}-0)^2+(y_{}-0)^2}^{})^2
r^2=(x_{}-0)^2+(y_{}-0)^2The equation of the circle is:
r^2=(x_{}-0)^2+(y_{}-0)^2

User BSevo
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