The equation of the circle can be determined as follow:
If you have the center in the point (0,0)
and r = 12
You use the next formula:
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/be685jmxw05hm2tq94m5iuge2xjynn1hfn.png)
Where
the d is equal to the r
x1 and y1= (0,0) (the center point)
x2 and y2 = (x,y)
Then we have:
![r=\sqrt[]{(x_{}-0)^2+(y_{}-0)^2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tora1q5y324iqwm6219jpa7dd54hn27q1t.png)
![r^2=(\sqrt[]{(x_{}-0)^2+(y_{}-0)^2}^{})^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/d5bs9inb2r3ile212wvbpogv4r5ul11pji.png)

The equation of the circle is:
