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describe the center and spread of the data using the more appropriate status either the mean median range interquartile range or standard division

User Harsh J
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\begin{gathered} \mleft\lbrace1,12,2,9,2,3,7,3,3,6\mright\rbrace \\ \operatorname{mean}=(1+12+2+9+2+3+7+3+3+6)/(10)=(48)/(10)=4.8 \end{gathered}
\sigma=\sqrt[]{\frac{\sum ^N_(i\mathop=1)(x-\operatorname{mean})^2}{N}}=3.4

User Vinodk
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