Question

2. What is the temperature (°C) of 1.50 moles of gas stored in a 10.0 L container at 1558 mm

Hg? (R=0.082 L atm/ mol K, 1.00 atm = 760 mm Hg
(4 points)

Answer 1

-106°C

Step-by-step explanation:

1558 mmHg / 1 × 1 atm / 760. mmHg = 2.05 atm

PV = nRT

2.05 atm (10.0 L) = 1.50 mol (0.082 atmL/molK) T

20.5 atmL = (0.123 atmL/K) T

K/0.123 atm L × 20.5 atmL = (0.123 atmL/K) T × K/0.123 atmL

166.666 K = T

167 K = T (sig figs)

K = °C + 273

167 - 273 = °C - 273

-106 = °C