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X- sq root 6 is a factor of x^4-36 true or false

User Sweetz
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1 Answer

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We want to know if (x-sqroot(6)) is a factor of (x^4 - 36)

That's mean:


(x^4-36)=(x-\sqrt[]{6})\text{ P(x)}

Where P(X) is a polinomial.

In this case, if x = sqroot(6) the polinomail (x^4 - 36) must be zero, that's mean sqroot(6) is a root (or a zero) of (x^4-36).

So, if we evaluate (x^4 - 36) in x=sqroot(6):


(\sqrt[]{6})^4-36=6^2-36=0

So, the answer is true.

User Shehaaz
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