High School A currently has 900 students and is projected to grow by 50 students each year.
We can write an equation using the above information
![A=900+50t](https://img.qammunity.org/2023/formulas/mathematics/college/fwr3cmk1rvsz2297s8pezyjfx3cqyrttyh.png)
Where A represents the number of students in High School A in t years.
High School B currently has 500 students and is projected to grow by 100 students each year.
We can write an equation using the above information
![B=500+100t](https://img.qammunity.org/2023/formulas/mathematics/college/rzg4cztp30hcsttg83nvwbgrug6b3zqvau.png)
Where B represents the number of students in High School B in t years.
Let us graph these two equations
Determine which high school is projected to have more students in 4 years.
Let us substitute t = 4 into both equations
![\begin{gathered} A=900+50t \\ A=900+50(4) \\ A=900+200 \\ A=1100 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3b2b3skydgrouoa4dq0oe51utzdim79wl3.png)
High school A is projected to have 1100 students in 4 years.
![\begin{gathered} B=500+100t \\ B=500+100(4) \\ B=500+400 \\ B=900 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ut75sdvsfz791buwrek79m4jqbuf86isiz.png)
High school B is projected to have 900 students in 4 years.
Therefore, high school A is projected to have more students (1100) as compared to high school B (900) in 4 years.