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Is the following process correct? If not, which step is where the error occurs, justify your answer. Then rework the problem to find the correct answer.

Is the following process correct? If not, which step is where the error occurs, justify-example-1

1 Answer

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We are given the following absolute value equation


|4x-1|=5x+37

Let us solve the problem then we will compare it with the given solution.


\begin{gathered} |4x-1|=5x+37 \\ 4x-1=\pm(5x+37) \end{gathered}

Now we will solve for the positive and negative sign separately


\begin{gathered} 4x-1=5x+37 \\ 4x-5x=37+1 \\ -x=38 \\ x=-38 \end{gathered}
\begin{gathered} 4x-1=-5x-37 \\ 4x+5x=-37+1 \\ 9x=-36 \\ x=(-36)/(9) \\ x=-4 \end{gathered}

Comparing it with the given solution, there is an error on the left-hand side step 2. (the sign of 38 should be positive but in the figure, it is shown negative)

Now let us substitute the obtained x values into the original absolute value equation and check if they satisfy the equation.

For x = -4:


\begin{gathered} |4(-4)-1|=5(-4)+37 \\ |-16-1|=-20+37 \\ |-17|=17 \\ 17=17 \end{gathered}

Hence, x = -4 is a valid solution.

For x = -38:


\begin{gathered} |4(-38)-1|=5(-38)+37 \\ |-152-1|=-190+37 \\ |-153|=-153 \\ 153\\e-153 \end{gathered}

Hence, x = -38 is not a valid solution.

The above is an example of an extraneous solution.

An extraneous solution is a solution that we get during the process of solving an equation but it is not really the solution meaning that it does not satisfy the equation!

Therefore, x = -4 is the only solution to the given equation.

User Randall Helms
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