Question

You and some friends are duck pin bowling. You’re up and you roll your bowling ball (m = 1.6kg) down the lane. It collided with one pin (0.68kg) on the end in a perfectly elastic one dimensional collision. If the ball was moving at a velocity of 6 m/s just before it hits the pin, what is the velocity of the bowling pin after the collision?

Answer 1

Given:

The mass of the bowling ball is m1 = 1.6 kg

The mass of the pin is m2 = 0.68 kg

The initial velocity of the ball is

`v_i=\text{ 6 m/s}`

Required: Velocity of the bowling pin after the collision.

Step-by-step explanation:

According to the conservation of momentum, the velocity after the collision will be

`\begin{gathered} m1v_i+m2*0\text{ =\lparen m1+m2\rparen v}_f \\ v_f=(m1v_i)/(m1+m2) \\ =(1.6*6)/(1.6+0.68) \\ =4.21\text{ m/s} \end{gathered}`

Final Answer: The velocity of the bowling pin after the collision is 4.21 m/s