Question

Can you help show me the conversion works for this problem in my online homework please?

Answer 1

There are 2.04*10^-4 moles of hydrogen.

To start the calculation it is necessary to use the molar mass of glycine:

- Glycine molar mass: 75.08 g/mol.

From the formula of glycine, we know that in 75.08g of glycine, there are 5 moles of hydrogen. So, in 3.06*10^-3g of glycine will be another amount of hydrogen, and we can calculate it with a mthematical Rule of Three:

`\begin{gathered} 75.08\text{gGlycine}-5\text{molHydrogen} \\ 3.06\cdot10^(-3)\text{gGlycine}-x=\frac{3.06\cdot10^(-3)\text{gGlycine}\cdot5\text{molHydrogen}}{75.08\text{gGlycine}} \\ x=2.04\cdot10^(-4)\text{molHydrogen} \end{gathered}`

So, there are 2.04*10^-4 moles of hydrogen in 3.06*10^-3g of glycine.