157k views
0 votes
A chemist has 30% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 570 liters of 31% acid solution? Work area number of liters | acid strength | Amount of acid 30% acid solution 60% acid solution 31% acid solution liters of 30% acid liters of 60% acid

User Lee Oades
by
8.7k points

1 Answer

1 vote

Let the amount of 30% acid solution be a

Let the amount of 60% acid solution be b

Given, "a" and "b" mixed together gives 570 liters of 31% acid. We can write:


0.3a+0.6b=0.31(570)

Also, we know 30% acid and 60% acid amounts to 570 liters, thus:


a+b=570

The first equation becomes:


0.3a+0.6b=176.7

We can solve the second equation for a:


\begin{gathered} a+b=570 \\ a=570-b \end{gathered}

Putting this into the first equation, we can solve for b. The steps are shown below:


\begin{gathered} 0.3a+0.6b=176.7 \\ 0.3(570-b)+0.6b=176.7 \\ 171-0.3b+0.6b=176.7 \\ 0.3b=176.7-171 \\ 0.3b=5.7 \\ b=(5.7)/(0.3) \\ b=19 \end{gathered}

So, a will be:

a = 570 - b

a = 570 - 19

a = 551

Thus,

551 Liters of 30% acid solution and 19 Liters of 60% acid solution need to be mixed.

User Mauker
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.