1 Answer

Khakishoiab · Answer 1 · 2023-04-16T10:21:24+0000

Given that mass of bullet, m = 9.50 g = 0.0095 kg

speed of bullet, v is 1.30 km/s

(a) Kinetic energy is given by the formula

$K\mathrm{}E\text{. = }(1)/(2)mv^2$

Substituting the values in the above formula, we get

$K\mathrm{}E\mathrm{}=(1)/(2)(0.0095)(1.30)^2=8.0275*10^(-3)\text{ J}$

(b) Speed of bullet is v/2

Sustituting this value in the formula of kinetic energy, we get

$\begin{gathered} K.E._1=\text{ }(1)/(2)m((v)/(2))^2 \\ =(1)/(2)*(0.0095)*((1.30)/(2))^2 \\ =2.0068*10^{-3\text{ }}J \end{gathered}$

(c) Speed of bulllet becomes 2v

Sustituting this value in the formula of kinetic energy, we get

$\begin{gathered} K.E._2=\text{ }(1)/(2)m(2v)^2 \\ =(1)/(2)*(0.0095)*(2*1.30)^2 \\ =0.03211J \end{gathered}$

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