Question

A number is selected randomly from a container containing all the integers from 10 to 50. Find P(Prime|between 11 and 30).A. 7/10B. 1/2C. 1D. 3/10

Answer 1

Given:

Numbers in the container: All integers from 10 to 50

Let's find P(Prime numbers| numbers between 11 and 30).

Here, we are to find the conditional probability.

Apply the formula:

P(Prime|between 11 and 30) = P(prime numbers and between 11 and 30) ÷ P(numbers between 11 and 30).

Where:

• Prime numbers between 11 and 30 = 11 , 13 , 17 , 19 , 23 , 29 =6 numbers

,

• Intergers from 10 to 50 = 41 integers.

To find the probability, we have:

`\begin{gathered} P(Prime|between11and30)=((6)/(41))/((20)/(41)) \\ \\ =(6)/(41)\ast(41)/(20) \\ \\ =(6)/(20) \\ \\ =(3)/(10) \end{gathered}`

Therefore, we have:

P(Prime|between 11 and 30) = 3/10.

ANSWER:

D. 3/10