Question

How many moles of copper(l) oxide contain 1.20 x 10^23 copper atoms? Include units and name of atom/molecule.

Answer 1

Number of moles = 0.1993 mole

Explanation:

Given particles

`\begin{gathered} \text{Number of particles = 1.20 }\cdot10^(23) \\ \text{Avogadro's number = }6.022\cdot10^(23) \end{gathered}`

The formula for calculating moles is written below

`\text{Number of moles = }\frac{Number\text{ of particles}}{\text{Avogadro's number}}`

The next thing is to substitute the above parameters into the above formula

`\begin{gathered} \text{Number of moles = }(1.20\cdot10^(23))/(6.022\cdot10^(23)) \\ \text{Number of mole = }(1.20)/(6.022) \\ Number\text{ of moles = 0.1993 mole} \end{gathered}`