SOLUTION
Consider the image below
The ratio of the side is given by
![\begin{gathered} \text{large to small} \\ \frac{\text{large}}{small}=\frac{length\text{ of the side of the large triangle}}{Length\text{ of the side of small triangle }}=(10)/(5)=(2)/(1) \\ \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wg6eqjo6x186gtol5pa157n28q1anshbgp.png)
Since the ratio of the side is the scale factor
![\text{the scale factor =}(2)/(1)](https://img.qammunity.org/2023/formulas/mathematics/college/nanbg5nd70sfl0l9xpswld0ulo9s5oa53v.png)
hence The raio of the perimeters is the scale factor
Therefore
The ratio of their parimeter is 2 : 1
The ratio of the Areas is square of the scale factor
![\text{Ratio of Area =(scale factor )}^2](https://img.qammunity.org/2023/formulas/mathematics/college/h0yea8pkn5f8mf68nfp6nto40r7qnmckh0.png)
Hence
![\begin{gathered} \text{ Since scale factor=}(2)/(1) \\ \text{Ratio of Area=}((2)/(1))^2=(2^2)/(1^2)=(4)/(1) \\ \text{Hence} \\ \text{Ratio of their areas is 4 : 1} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5lbk80fl62ptuy2nseu1ij240cvuuanp8n.png)
Therefore
The ratio of their Areas is 4 :1