First set x-2 to be 0. The result (x) would be 2. Then, try any number that is below 2, let’s say x=0. Substituting G(0) = |0-2|, you would get that y = 2. This is when you can draw a line starting from point P(2, 0) (for when y = 0) and passing through point P(0, 2) (for when x = 0). Now try any number for x bigger than 2, let’s say 4. Substituting that into the function, you get G(4) = |4-2|, which means y = 2. Now, you can draw a final line starting from P(2, 0) (for when y = 0), and passing through P(4, 2) (for when x = 4). If the answer wanted to show a graph with this configuration, you'd get something in the lines of a V shape, with its point of convergence for y being 0 (I’m talking about the point when the 2 lines converge). You’re welcome.