Question

As I am completely brand new to this subject/branch of mathematics, please explain thoroughly, step by step on how to complete this This is a practice from my ACT prep guide take your time, as there is no rush *Ignore the last answer option

Answer 1

Remember that

The difference of squares is of the form

`(a+b)(a-b)=a^2-b^2`

In this problem we have

`(3x-4y^2)(3x+4y^2)`

so

a=3x

b=4y^2

therefore

Apply the difference of squares

`(3x-4y^2)(3x+4y^2)=(3x)^2-(4y^2)^2=9x^2-16y^4`