• We are given that Lidocaine is available as 0.5%(w/v) , 0.5%(w/v) represents the amount of Lidocaine in grams per 100mL. so, 0.5% is the same as 0.5g of Lidocaine in 100ml.
,
• Since our solution has a volume of 6.0mL:
mass of Lidocaine = 6mL * (0.5g /100mL)
= 0.03g of Lidocaine in 6.0mLsolution.
This means that, in 6.0ml of this injection solution, we have 0.03g of Lidocaine .