Question

A sample of neon gas occuples a volume of 7.5L at 35 °C. If the temperature is increased to 45°C, what is the new volume? K=273+•C

Answer 1

Assuming the pressure remains same, we can use Charles' Law here

i.e.

`(V1)/(T1)=\text{ }(V2)/(T2)`

Here, V1 = 7.5 l, T2 = 35 +273= 308 K

T2= 45+273 = 318 K, we need to find V2

`(7.5)/(308)=\text{ }(V2)/(318)`
`So,\text{ V2 = 7.74 L}`