Question

Precalc please help Answers:A. 5 sin 60°/sin 70°B. 5/sin 50° sin 70°C. 5/sin 50°D. 5 sin 50°/sin 70°

Answer 1

step 1

Find out the measure of angle P

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

P+Q+R=180 degrees

substitute given values

P+70+60=180

P=180-130

P=50 degrees

step 2

Applying the law of sines

QR/sin P=PR/sin 70

substitute given values

QR/ sin 50=5/sin 70

QR=(5/sin 70)*sin 50

the answer is option D