Question

Hello can you help me with this question and this a homework assignment

Answer 1

Problem

Solution

For this case we can use the Cosine law and we have:

`\cos (c)=(a^2+b^2-c^2)/(2ab)=(35^2+56^2-33^2)/(2\cdot35\cdot56)=0.8346938776`
`\cos (b)=(a^2+c^2-b^2)/(2ac)=(35^2+33^2-56^2)/(2\cdot35\cdot33)=-0.356`
`\cos (a)=(c^2+b^2-a^2)/(2cb)=(33^2+56^2-35^2)/(2\cdot33\cdot56)=0.8116883117`

And then we can find the angles with the arcos like this:

`<\gamma=ar\cos (0.8346938776)=33.42`
`<\beta=ar\cos (-0.356)=110.85`
`<\alpha=ar\cos (0.8116883117)=35.74`

Can you see the new values for gamma and alfa