Recall that a function is continuous at a point if the limit as the variable approaches a value is the same as the value of the function at that point.
Now, notice that, using the definition of the function:
![\begin{gathered} \lim_(x\to1^+)f(x)=√(1)+2=3, \\ \lim_(x\to1^-)f(x)=3, \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v63axl8gk299jjrfpsvs93o93f20vt3l8t.png)
therefore:
![\lim_(x\to1)f(x)=3.](https://img.qammunity.org/2023/formulas/mathematics/college/wrqdcoxp1l4y9vfrvkkcgmfwzdatjkxe1x.png)
Given that the limit and the value of the function at x=1 are equal, the function is continuous at x=1.
Answer: It is continuous at x=1.