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Solve the following addition and subtraction problems.3 km9hm9dam19 m+7km2 dam5sq km95 ha8,994sq m+11sq km11 ha9,010sq m44m−5dm72km47hm2dam−11 km55hm

User Partkyle
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As a well accepted rule to solve this problem, we would transform all values to the lower units.

so for the first question:

3 km 9hm 9 dam 19 m + 7 km 2 dam

3,000 m 900 m 90 m 19 m + 7,000 m 20 m

= 4,009 + 7,020

= 11,029 m

The second question:

5 sq.km 95 ha 8,994 sq.m + 11 sq.km 11 ha 9,010 sq.m

5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq 9,010 sq m

= 5,103,994 sq m + 11,119,010 sq m

= 16,223,004 sq m

The third question:

44 m - 5 dm

44 m - 0.5 dm

= 43.5 m

The fourth question:

72 km 47 hm 2 dam - 11 km 55 hm

72,000 m 4,700 m 20 m - 11,000 m 5,500 m

= 76,720 m - 16, 500 m

= 60,220 m

User Spencer Cooley
by
8.5k points

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