Step 1:
Draw the table for the input x and output y.
Step 2:
From the table, we can see that the function is an exponential function.
![\begin{gathered} y=x^2 \\ \text{for x = 0, y = 0} \\ \text{for x = 1, y = 1} \\ \text{for x = 2, y = 4} \\ \text{for x = 3, y = 9} \\ \text{Hence, y = x}^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gevc4uqd3scwrk9vnf2qe4mvi5f6btabe0.png)
Step 2:
Find the inverse of the function.
![\begin{gathered} y=x^2 \\ \text{The inverse of } \\ y=x^2 \\ is \\ y\text{ = }\pm\sqrt[]{x} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mljxmgtehcjeh1uqtlmdrnmcos3ttqearh.png)
Step 3:
The two graphs below, show the graph of the inverse for both negative and positive square roots of x.
![\text{The blue graph above shows the graph for y = +}\sqrt[]{x}](https://img.qammunity.org/2023/formulas/mathematics/high-school/if9k2go866dq99jxceav64ikxccmqt04xv.png)
![\text{The blue graph above shows the graph of y = -}\sqrt[]{x}](https://img.qammunity.org/2023/formulas/mathematics/high-school/97hoppybvswfre74cxex2zn61euuq6k5o2.png)
Final answer
The blue graph is the inverse of the red graph.