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2200 J of work was done in 10 s. What is the amount of power?
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2200 J of work was done in 10 s. What is the amount of power?

User Gabriele Franco
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We will have that the power will be:


\begin{gathered} P=(W)/(\Delta t)\Rightarrow P=(2200J)/(10s) \\ \\ \Rightarrow P=220J/s\Rightarrow P=220W \end{gathered}

So, the power was 220 Watts.

User Max Wyss
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