Question

2200 J of work was done in 10 s. What is the amount of power?

Answer 1

We will have that the power will be:

`\begin{gathered} P=(W)/(\Delta t)\Rightarrow P=(2200J)/(10s) \\ \\ \Rightarrow P=220J/s\Rightarrow P=220W \end{gathered}`

So, the power was 220 Watts.