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Mr. Mangan now sees a hoard of zombies running toward him. There are toomany for him to fight, so he makes a run for it. Starting from rest andaccelerating at a rate of 7 m/s2, he reaches a final velocity of 25 m/s. Howmuch time did it take for him to reach his final velocity?

1 Answer

6 votes

Given data

*The given initial velocity is u = 0 m/s

*The given acceleration is a = 7 m/s^2

*The given final velocity is v = 25 m/s

The formula for the time taken to reach his final velocity is given by the kinematic equation of motion as


\begin{gathered} v=u+at \\ t=(v-u)/(a) \end{gathered}

Substitute the known values in the above expression as


\begin{gathered} t=(25-0)/(7) \\ =3.57\text{ s} \end{gathered}

Thus, the time taken to reach his final velocity is t = 3.57 s

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