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the day of the lowest show the most ever in a single day by random sample of 13 students calculate the 38th and the 60th percentile of data

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We have that the sample consist in n=13 students. The percentile formula is given by


P_x=(x)/(100)* n\text{ position}

where x denotes the percentaje. In the first case, p=38, then, we have


\begin{gathered} P_(38)=(38)/(100)*13\text{ position} \\ P_(38)=4.94\text{ position} \end{gathered}

then, we get


P_(38)=41

that is, P_38 corresponds to 41 miles driven.

In the second case, by substituting x=60 in our formula, we get


\begin{gathered} P_(60)=(60)/(100)*13\text{ position} \\ P_(60)=7.8\text{ position} \end{gathered}

which gives


P_(60)=56

that is, P_60 corresponds to 56 miles driven.

Then, the answers are:


P_(38)=41

This means that approximately 38% of the data lie below 41, when the data are ranked.


P_(60)=56

This means that approximately 60% of the data lie below 56, when the data are ranked.

User Nishant Mendiratta
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