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Discriminant for 2n^2+8n+1=-7

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The given equation is


\begin{gathered} 2n^2+8n+1=-7 \\ 2n^2+8n+1+7=0 \\ 2n^2+8n+8=0 \end{gathered}

Where a = 2, b = 8, and c = 8.

The discriminant formula is


D=b^2-4ac

Let's replace the values


D=(8)^2-4(2)(8)=64-64=0

The equation has one real solution.

User CBRRacer
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