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Two drops of mercury each has a charge on 5.44 nC and a voltage of 235.15 V. If the two drops are merged into one drop, what is the voltage on this drop?
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Two drops of mercury each has a charge on 5.44 nC and a voltage of 235.15 V. If the two drops are merged into one drop, what is the voltage on this drop?

User Eran Galperin
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1 Answer

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To find the voltage of the combined drops, we can just add the voltage of both drops together.

2(235.15) = 470.3 Volts

User Mouhamed
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