Question

6. sin D - Ог F 25 ot E 7. cos F. 24 8. sin F Nodule 13

Answer 1

In the given triangle :

FD = 25, FE = 7, DE = 24

SinD

From the trignometric ratio of sin: It express as the ratio of measurement of the side opposite to the angle to the measurement of hypotenuse of triangle DEF,

So, the SinD is express as :

`\begin{gathered} \sin D=\frac{Opposite\text{ side}}{Hypotenuse} \\ \sin D=(FE)/(DF) \\ \sin D=(7)/(25) \end{gathered}`

sin D = 7/25

cos F

From the trignometric ratio of cos : It expresses as the ratio of measurement of the side adjacent to the angle and to the hypotenuse of the triangle

So, the Cos F is express as :

`\begin{gathered} \cos F=\frac{Adjacent\text{ side}}{Hypotenuse} \\ \cos F=(FE)/(DF) \\ \cos F=(7)/(25) \end{gathered}`

cos F = 7/25

Sin F

From the trignometric ratio of sin: It express as the ratio of measurement of the side opposite to the angle to the measurement of hypotenuse of triangle DEF,

so, Sin F is express as :

`\begin{gathered} \sin F=\frac{Opposite\text{ side}}{Hypotenuse} \\ \sin F=(DE)/(DF) \\ \sin F=(24)/(25) \end{gathered}`

sin F = 24/25

Answer :

sin D = 7/25

cos F = 7/25

sin F = 24/25