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Nancy plans to take her cousins to an amusement park. She has a total of $100 to pay for 2 different charges. • $5 admission per person • $3 per ticket for rides Which inequality could Nancy use to determine y, the number of tickets for rides she can buy if she pays the admission for herself and x cousins? A. 5y + 3(x + 1) >= 100 B. 5(x + 1) + 3y > 100 C. 5(x + 1) + 3y =< 100 D. 5y + 3(x + 1) < 100

1 Answer

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ANSWER


C.5(x\text{ + 1) + 3y }\leq100

Step-by-step explanation

Nancy has $100.

The charges are:

=> $5 admission per person. She has x cousins and herself to pay for, this means that she pays $5 for (x + 1) persons.

The admission charge is therefore:

$5 * (x + 1) = $5(x + 1)

=> $3 per ticket for rides. The number of rides she can pay for is y. So the charge for rides is:

$3 * y = $3y

Since she only has $100, everything she pays for can only be less than $100 or equal to $100.

This means that, if we add all the charges, they must be either less than or equal to $100.

That is:


5(x\text{ + 1) + 3y }\leq100

That is Option C.

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