Question

G(x)= x^2+3h(x)= 4x-3Find (g-h) (1)

Answer 1

Given:-

`g(x)=x^2+3,h(x)=4x-3`

To find:-

`(g-h)(1)`

At first we find the value of (g-h)(x), so we get,

`\begin{gathered} (g-h)(x)=g(x)-h(x) \\ =x^2+3-(4x-3) \\ =x^2+3-4x+3 \\ =x^2-4x+6 \end{gathered}`

So the value of,

`(g-h)(x)=x^2-4x+6`

So the value of (g-h)(1) is,

`\begin{gathered} (g-h)(x)=x^2-4x+6 \\ (g-h)(1)=1^2-4*1+6 \\ (g-h)(1)=1-4+6 \\ (g-h)(1)=7-4 \\ (g-h)(1)=3 \end{gathered}`

So the required value is,

`(g-h)(1)=3`