Question

9. Determine the percent compositions for each of the following compounds. a. Ba(OH)2 b. copper (I) oxide C. Fe(C2H3O2)3 d. iron (III) nitrate hexahydrate (*see notes on backside to help with the hexahydrate part)

Answer 1

Iron 24.03%

Carbon 30.90%

Hydrogen 3.86%

Oxygen 41.20 %

Step-by-step explanation:

Here, we want to get the percentage composition of the given compound

What this means is that we want to get the percentage composition of each of the elements present in the compound

Firstly, we calculate the molar mass of the given compound

We can calculate the molar mass by adding the atomic masses of the elements and their multiplicities

Mathematically, we have that as:

`\begin{gathered} 56\text{ + 3\lparen2\lparen12\rparen + 3\lparen1\rparen +2\lparen16\rparen\rparen} \\ =\text{ 56 + 3\lparen24+3+32\rparen} \\ 56\text{ + 177 = 233 g/mol} \end{gathered}`

Now, let us get the percentage compositions

For Iron, we have:

`(56)/(233)*\text{ 100 \% = 24.03 \%}`

For Carbon, we have:

`(72)/(233)*\text{ 100 \% = 30.90 \%}`

For Hydrogen, we have:

`(9)/(233)*\text{ 100 \% = 3.86 \%}`

For Oxygen, we have:

`(96)/(233)*\text{ 100 \% = 41.20\%}`