Answer:
There would be a change in the color of the potassium iodide from yellowish-brown to colorless
Step-by-step explanation:
Here, we want to test for the presence of oxidizing agent by the use of potassium iodide
Since we already have the inference, we need to state what would be observed
Potassium iodide itself is a reducing agent
Thus, it becomes oxidized
In the process of being oxidized, there would be a color change
The color change observed will be from yellowish-brown to colorless