Question

Rosalyn is a teacher who plays a review game with her class. The game involves writing each student's name on an identical slip of paper and selecting students at random. Here's the makeup of her class: Grade 1 0 th 10 th 10, start superscript, start text, t, h, end text, end superscript 1 1 th 11 th 11, start superscript, start text, t, h, end text, end superscript 1 2 th 12 th 12, start superscript, start text, t, h, end text, end superscript Number of students 7 77 18 1818 5 55 Suppose that Rosalyn wants 2 22 different students, so she picks 2 22 names without replacing names between picks. What is the probability that both students selected are 1 1 th 11 th 11, start superscript, start text, t, h, end text, end superscript graders?

Answer 1

-11,000

Explanation:

Given the recursive function of a sequence to be a(n)=a(n−1)⋅10 and a(1) = -11

To find the fourth term of the sequence i.e when n = 4,

First when n = 2

a(2) = a(2-1)•10

a(2) = a(1)•10

a(2) = -11×10

a(2) = -110

When n =3

a(3) = a(2)•10

a(3) = -110×10

a(3) = -1100

When n = 4

a(4) = a(3)•10

a(4) = -1100×10

a(4) = -11,000

The 5th term of the sequence is -11,000