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Solve for u-6u+3(u-3)=12

User Habte
by
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1 Answer

4 votes

Answer: u=7

Given:


-6u+3(u-3)=12

- Distribute 3(u-3):


\begin{gathered} -6u+3(u-3)=12 \\ \Rightarrow-6u+3u-9=12 \end{gathered}

- Combine like terms:


\begin{gathered} \begin{equation*} -6u+3u-9=12 \end{equation*} \\ \Rightarrow-6u+3u=12+9 \\ \Rightarrow-3u=21 \end{gathered}

- Divide both sides by -3:


\begin{gathered} \begin{equation*} -3u=21 \end{equation*} \\ \Rightarrow(-3u)/(-3)=(21)/(-3) \\ \Rightarrow u=7 \end{gathered}

Therefore, u=7.

User Skmvasu
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