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Solve the absolute value inequity lx-5l>_ 1

User KGee
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1 Answer

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We are given the following the following inequality:

|x - 5| >= 1

When we have a inequality in the format:

|f(x)| >= a

There are two possible solutions.

Either f(x) <= -a or f(x) >= a

In this question:

|x - 5| >= 1

x - 5 <= -1

x <= -1 + 5

x <= 4

Or

x - 5 >= 1

x >= 1 + 5

x >= 6

In interval notation, the answer is:


(-\infty,4\rbrack\cup\lbrack6,+\infty)

The solution on the number line is:

Solve the absolute value inequity lx-5l>_ 1-example-1
User Ugoarangino
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