Question

A fisherman drops a fishing line into the sea. The end of the fishing pole is at an elevation of 5 feet. The hook that is in the water is at an elevation of -2 feet.cessmentThe number line shows their heights. Sea level is represented by 0.1. Write an absolute value expression telling how many feet the end of the fishingpole is above sea level. Evaluate the expression.2. Write an absolute value expression telling how many feet the hook is below sealevel. Evaluate the expression. 3. If the fishing line goes straight down into the water, what is the distance betweenthe end of the pole and the hook? Explain how you found this distance.

Answer 1

Given a fishing line acting as number line, find the asked distances

Step-by-step explanation:

given a fishing line having its one end of the fishing pole above the water. Let this distance be denoted by 'a'.

given that the hook of this fishing line is in the water hence, below the sea level. Let this depth be denoted by 'b'.

let the height of pole from sea-level be denoted by , height of the hook from sea level be denoted by and the length between pole end and hook be

since, this fishing line is acting as a number line with sea level as . The depth of fishing hook is negative and the elevation of the pole end is positive .

hence we get expressions,

for given values the evaluation of the expressions is,

Step-by-step explanation:

Answer 2

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

sea level = 0 ft

end of fishing pole = 5 ft

hook = -2 ft

Step 02:

absolute value:

distance between sea level and the end of fishing pole:

| 5 - 0| = | 5 | = 5 ft

distance between hook and sea level:

|0 - (-2)| = | 0 + 2| = |2| = 2 ft

distance between hook and the end of the fishing pole:

| 5 - (-2)| = | 5 + 2| = |7| = 7 ft

To find out the distance we must consider the entire interval.

That is the full solution.