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13 votes
13 votes
Solve the simultaneous equation


3x-4y=11
9x+2y=5

User Ananda Subasinghe
by
2.5k points

2 Answers

7 votes
7 votes

Answer:

Below in bold.

Explanation:

3x-4y=11

9x+2y=5

Multiply the first equation by 3:

9x - 12y = 33

Subtract the above from the second equation:

2y - (-12y) = 5 - 33

14y = -28

y = -2.

Now plug y = -2into the first equation:

3x - 4(-2) = 11

3x = 11 - 8 = 3

x= 1.

User Neizan
by
2.9k points
22 votes
22 votes

Answer:

I assume you are looking for the x and y values of the two equations? if not message me!

y=–2

x=1

Explanation:

Multiply the first/top tearm by –3 so we can "get rid of" the X's with the addition of both equations. we are then left with: 14y=-28

We can now divide both sides by 14 to get y by itself so we are left with: y=–2

plugging our y value back into the first equation we get: 3x+8=11. we subtract 8 from both side and are left with: 3x=3. dividing both side by 3 we can get x by itself and are left with: x=1

To check, we plug x and y both into the first equation we get: 3+8=11 (which it does). Or we can plug both of them into the second equation and we get:9-4=5 (which it does)

User Fscheidl
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2.6k points