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A car initially at rest travels with a uniform acceleration of 8 m / s^2 . Calculate the distance covered by the car in 3 s .

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We know that

• The initial velocity is zero because it starts from rest.

,

• The acceleration is 8 m/s^2.

,

• The time elapsed is 3 seconds.

Use a formula that relates initial velocity, acceleration, time, and distance.


d=v_0t+(1)/(2)at^2

Use the given magnitudes to find d.


\begin{gathered} d=0\cdot3\sec +(1)/(2)\cdot(8\cdot(m)/(s^2))(3\sec )^2 \\ d=4\cdot(m)/(s^2)\cdot9s^2 \\ d=36m \end{gathered}

Therefore, the distance covered is 36 meters.

User LJH
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