Question

Simplify 3√12 +8✓12 - √6 how

Answer 1

In order to simplify this equation, we are going to start by simplifying the radicals.

`\sqrt[]{12}=\sqrt[]{2^2\cdot3}=\text{2}\sqrt[]{3}`

Now we have the radicals simplified and we are going to replace them on the equation that we already have.

`\begin{gathered} 3\cdot(2\sqrt[]{3})+8\cdot(2\sqrt[]{3})-\sqrt[]{6} \\ 6\sqrt[]{3}+16\sqrt[]{3}-\sqrt[]{6} \\ 22\sqrt[]{3}-\sqrt[]{6} \end{gathered}`